Lua-Funktionen mit variabler Anzahl Argumente

local arg = {...}

for i,v in ipairs{...} do
end

for i=1,arg.n do
end

local arg = {...}

for i,v in ipairs{...} do

function getMessage(key, ...)
  local arg = {...}
  local value = messages[language][key]
  if value == nil then
    value = messages[messages.defaultLanguage][key]
  end
  
  for i = 1, #arg do
    value = string.gsub(value, "#" .. tostring(i) .. "#", arg[i])
  end
  
  return value
end

function getMessage (key, replace1, replace2, replace3, replace4)
  local value = messages[objLanguage][key]

-- Ersetzen der #n# Platzhater. Funktionbricht ab, sobald der erste "nil"-Wert gesehen wird
  if replace1 ~= nil then
    value = string.replace(value, "#1#", replace1)
    if replace2 ~= nil then
      value = string.replace(value, "#2#", replace2)
      if replace3 ~= nil then
        value = string.replace(value, "#3#", replace3)
        if replace4 ~= nil then
          value = string.replace(value, "#4#", replace4)
        end
      end
    end
  end
  return value
end

function string.replace(str, old, new)
  first,last = string.find(str, old) --Sucht in "str" die Zeichenkette "old" und gibt den Start und Endwert derselben zurück
  if first == nil then  -- Keine Üereinstimmung gefunden -> Abbruch
    return str
  end
  return string.sub(str, 1, first-1) .. new .. string.sub(str, last+1) -- Setzt an der gefundenen Stelle "new" ein
end

function string.replace(str, old, new)
  -- Looking in str for old, returns first and last
  first,last = string.find(str, old)
  -- If we found something ...
  while first ~= nil do
    -- ... than replace old string with new string one
    str = string.sub(str, 1, first-1) .. new .. string.sub(str, last+1)
    -- Look for the next occurence of old in str
    first,last = string.find(str, old)
  end
  return str
end